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Post by skinbath on Sept 20, 2005 19:17:58 GMT -4
I was watching a programme on T.V the other night about black holes and decided to impart some utterly useless info.......for any musicians out there...... When enough matter is packed tightly enough around a black hole,a "ring tone" is produced that equates to the note Bb 57 octaves below middle C.....any wind or brass players fancy giving that a go...... Concert pitch "A" = 440 Hertz........anyone know how the above would equate on the frequency scale?
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Post by Martina W. on Sept 23, 2005 17:37:44 GMT -4
Concert pitch "A" = 440 Hertz........anyone know how the above would equate on the frequency scale? Middle C is 261,626 Hertz. For every octave you go down the frequency is halved.
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Post by skinbath on Sept 23, 2005 22:20:54 GMT -4
You`re right martinaw....being thoroughly ridiculous here and using modern standardisation.... A=440Hz ,whole tone above,B=493Hz (my rounding off), I`ll round off Bb at approx 466hz....reduce by half 58 times gives us something that equates to a very low rumble indeed..... I was just intrigued as to how and why those in the relevant astronomical/cosmic fields involved would use this information..... any thoughts? edit...It may be that I`ve looked at this in a back to front fashion,i.e...this is the technique used to illustrate the presence of said matter....
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